How do you evaluate #(0.5x + 2) ( 0.5x + 2) #?

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Answer 1 · 2017-06-30T10:09:50

See a solution process below:

We can first, rewrite this expression as:

#(0.5x + 2)^2#

We can then use this rule for the special form of quadratics:

#(a + b)^2 = a^2 + 2ab + b^2#

Substituting:

#0.5x# for #a#

#2# for #b#

Gives:

#(0.5x + 2)^2 = (0.5x)^2 + (2 * 0.5x * 2) + 2^2 =#

#0.25x^2 + 2x + 4#