How do you evaluate # 11+ 7- 2\times 3+ 8\div 2#? Prealgebra Arithmetic and Completing Problems Order of Operations 1 Answer Barney V. Jan 27, 2017 16 Explanation: #11+7-2 xx 3+8 -:2# #11+7-(2 xx 3)+(8-:2)# #:.11+7-6+4# #:.=16# Answer link Related questions What is #5-3*(-2) + |-3|#? What is #(3 * 10)^2 -: 5 - 4#? What is #2+2(2)^2(5)+ 8#? What is #14.3 * 2.1 * 8.9#? What is #8+(8+8-:4)+5^2#? How do you use PEMDAS to simplify #3 times 2 - (8+1) #? How do you simplify #3^4+2^3+8(4xx2-5) #? How do you simplify #4times3^2+3times4^2+2(3times4)^2#? How do you solve #30-5(4^2-8รท4-5*2)#? What is #7-3(-8-2) + 6 -:2#? See all questions in Order of Operations Impact of this question 1578 views around the world You can reuse this answer Creative Commons License