How do you evaluate #2( 3) + 12- ( 4\cdot 3)#?

1 Answer
Mar 11, 2018

Answer:

#2(3)+12-(4*3)=6#

Explanation:

We evaluate this using the order of operations:

  1. Parenthesis
  2. Exponents/Roots
  3. Multiplication/Division
  4. Addition/Subtraction

In this case we start by evaluating the parenthesis:

#2(3)+12-(4*3)=2*3+12-12#

Next we evaluate multiplication:

#6+12-12#

And finally, we do addition and subtraction:

#6+12-12=18-12=6#