How do you evaluate #(- 2+ 4i ) ( - 3+ 6i )#?

1 Answer
turksvids
Dec 16, 2017

#-18-24i#

Explanation:

This is just like multiplying binomials (you might think of it as FOIL):

#(-2+4i)(-3+6i) #
#=(-2)(-3)+(-2)(6i)+(4i)(-3)+(4i)(6i)#
#=6-12i-12i+24i^2#
#=6-24i+24i^2#

Now, since #i^2=-1#:

#=6-24i-24#
#=-18-24i#

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