How do you evaluate #2\sqrt { 3} - 2\sqrt { 3} - 4\sqrt { 3} + 5#?

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Answer 1 · 2017-04-13T22:49:10

See the solution process below:

Factor #sqrt(3)# from the first three terms:

#(2 - 2 - 4)sqrt(3) + 5#

#-4sqrt(3) + 5#

If you want to eliminate the radical #sqrt(3) = +-1.732# rounded to the nearest thousandth.

Solution 1)

#(-4 * 1.732) + 5#

#-6.928 + 5#

#-1.928#

Solution 2)

#(-4 * -1.732) + 5#

#6.928 + 5#

#11.928#