# How do you evaluate 2\sqrt { 6} + 3\sqrt { 54}?

$11 \sqrt{6}$
$2 \sqrt{6} + 3 \sqrt{54}$
= $2 \sqrt{6} + 3 \sqrt{9 \times 6}$
= $2 \sqrt{6} + 9 \sqrt{6}$
= $11 \sqrt{6}$