# How do you evaluate (2g - 1) ^2 - 2g + g ^2 for g = 3?

Mar 25, 2017

For $g = 3$, we have ${\left(2 g - 1\right)}^{2} - 2 g + {g}^{2} = 28$

#### Explanation:

Putting $g = 3$ in ${\left(2 g - 1\right)}^{2} - 2 g + {g}^{2}$,

we get ${\left(2 \times 3 - 1\right)}^{2} - 2 \times 3 + {3}^{2}$

= ${\left(6 - 1\right)}^{2} - 6 + 9$

= ${5}^{2} + 3$

= $25 + 3$

= $28$