How do you evaluate #3^ { 3} + 4( 4+ 1)#?

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Answer 1 · 2018-03-03T06:26:11

47

We use PEDMAS:

#color(red)(P)# - Parentheses (also known as Brackets)
#color(blue)(E)# - Exponents
#color(green)(D)# - Division
#color(green)(M)# - Multiplication(this has the same weight as D and so I gave it the same colour)
#color(brown)(A)# - Addition
#color(brown)(S)# - Subtraction - (again, same weight as A and so the same colour)

#3^3+4(4+1)#

We do #color(red)(P)# first:

#3^3+4(color(red)(5))#

Then #color(blue)(E)#:

#color(blue)(27)+4(5)#

Then #color(green)(M)#

#27+color(green)(20)#

Then #color(brown)(A)#

#color(brown)(47)#