How do you evaluate #3^ { - 3} \cdot 11#?
1 Answer
Mar 11, 2018
Explanation:
#"using the "color(blue)"law of exponents"#
#•color(white)(x)a^-mhArr1/a^m#
#rArr3^-3=1/3^3=1/27#
#rArr3^-3xx11#
#=1/27xx11/1=11/27#
