Question

How do you evaluate `3^ { 3} \cdot 9^ { - 1}`?

Answer 1

3

Explanation:

Law:
`a^3*a^3=a^(3+3)`
and

`(a^2)^3=a^6`

`3^3*9^-1`

`=3^3*(3^2)^-1`

`=3^3*3^-2`

`3^(3-2)`

`=3`

or

`3^3*3^-2`

`=3^3/3^2`

`=27/9`

`=3`