How do you evaluate #3( \frac { ( 6- 1) ^ { 2} } { 10+ 6} ) - 1#?

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Answer 1 · 2017-03-28T01:39:48

#3 11/16#

#3 ((6 - 1)^2/(10 + 6)) -1 = 3 ((5)^2/(16)) -1 #

#= 3 (25/(16)) -1 = 75/16 - 16/16 = (75 - 16) /25#

# = 59/16 = 3 11/16#

Answer 2 · 2017-03-29T08:41:29

#color(red)(3 11/16# or #color(red)(3.6875#

#3((6-1)^2/(10+6))-1#

#:.=3(5^2/16)-1#

#:.=3(25/16)-1#

#:.=75/16-1#

#:.=4 11/16-1#

#:.color(red)(=3 11/16# or# color(red)(3.6875#