How do you evaluate #3 times 2 5/6#?

1 Answer
Apr 2, 2017

#17/2#

Explanation:

To multiply that, rewrite the mixed fraction as an improper fraction.

Take the denominator of the mixed fraction, multiply it by the whole number and add the numerator. Whatever value you get becomes the numerator of the improper fraction over the denominator of the mixed fraction.

For #2(5)/6#, we multiply #6# by #2# and add the product to #5#

#(6*2)+5#

#12+5#

#17#

So our numerator is #17# over our denominator which is #6#

#:.#Our improper fraction for #2(5)/6# is #17/6#

Now we have

#3xx17/6#

Write #3# also as a fraction if you want.

#3/1xx17/6#

Multiply the numerators and the denominators or cancel out numbers that are divisible by others.

#cancel(3)^color(red)1/1xx17/(cancel6^color(red)2)#

#rArr17/2#