How do you solve #3x ^ { 2} + 3= 75#?

1 Answer
Sep 14, 2017

See a solution process below:

Explanation:

First, subtract #color(red)(3)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#3x^2 + 3 - color(red)(3) = 75 - color(red)(3)#

#3x^2 + 0 = 72#

#3x^2 = 72#

Next, divide each side of the equation by #color(red)(3)# to isolate #x^2# while keeping the equation balanced:

#(3x^2)/color(red)(3) = 72/color(red)(3)#

#(color(red)(cancel(color(black)(3)))x^2)/cancel(color(red)(3)) = 24#

#x^2 = 24#

Now, take the square root of each side of the equation to solve for #x# while keeping the equation balanced. Remember, the square root of a number produces both a negative and a positive result:

#sqrt(x^2) = +-sqrt(24)#

#x = -sqrt(4 * 6)# and #x = +sqrt(4 * 6)#

#x = -sqrt(4)sqrt(6)# and #x = sqrt(4)sqrt(6)#

#x = -2sqrt(6)# and #x = 2sqrt(6)#

Or, if a single number is needed:

#x = -2 * 2.4494# and #x = 2 * 2.4494#

#x = -4.899# and #x = 4.899# rounded to the nearest thousandth