How do you evaluate #(( 3x - 2) ( 9x ^ { 2} + 6x + 4) )#?

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Answer 1 · 2017-11-18T19:17:48

#= 27x^3-8#

They are asking to simplify it. You can not evaluate it because they don't give the number for x.

So, let's get started....

#(3x-2)(9x^2+6x+4)#

Let's start by using the distributive property

#=(3x)(9x^2)+(3x)(6x)+(3x)(4)+(-2)(9x^2)+(-2)(6x)+(-2)(4)#

#=27x^3 + 18x^2 + 12x-18x^2 - 12x - 8#

Combine the like terms

#=27x^3 cancelcolor(red)(+18x^2) cancelcolor(red)(-18x^2) cancelcolor(green)(-12x) cancelcolor(green)(+12x) -8#

#=27x^3 -8#