How do you evaluate #(3x^{2}y^{5})^{0}#?

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Answer 1 · 2018-01-30T04:17:20

#color(blue)((3x^{2}y^{5})^{0} = 1#

Given:

#color(blue)((3x^{2}y^{5})^{0}#

The rule for zero as an exponent is that any number or variable (apparently, except zero itself) raised to the zero power is equal to 1.

For example:

#color(brown)(a^0 = 1#

Hence we can simplify #color(blue)((3x^{2}y^{5})^{0}# as

#color(blue)((3x^{2}y^{5})^{0} = 1#