# How do you evaluate (4- 2) \cdot 6\div 3+ ( 5- 2) ^ { 2}?

Mar 3, 2018

See below.

#### Explanation:

We must use order of operations to solve this problem.

P: parentheses
E: exponents
M: multiplication
D: division
S: subtraction

Now, since the problem is $\left(4 - 2\right) \cdot 6 \div 3 + {\left(5 - 2\right)}^{2}$, you must look and say to yourself, "Is there any parentheses?"

$\textcolor{b l u e}{\left(4 - 2\right)} \cdot 6 \div 3 + {\textcolor{b l u e}{\left(5 - 2\right)}}^{2}$

Now, solve those parentheses, and you get

$2 \cdot 6 \div 3 + {3}^{2}$

So now, you must look at the equation and say to yourself, "Any exponents?" Since ${3}^{2}$ is an exponent, you must solve the problem $3 \cdot 3$. Now, you are left with

$2 \cdot 6 \div 3 + 9$

Time for multiplication! Look for any multiplication, and solve it. You are now left with

$12 \div 3 + 9$

Since there is division, you must now solve that, and you will end up with

$4 + 9$

which can be solved using addition, to get your final answer of $13$.