# How do you evaluate (4- 7) ^ { 2} \div ( 7- 6) ^ { 3}?

Jan 31, 2018

9

#### Explanation:

${\left(4 - 7\right)}^{2} = 9$
${\left(7 - 6\right)}^{3} = 1$
9÷1=9

Feb 1, 2018

${\left(4 - 7\right)}^{2} \div {\left(7 - 6\right)}^{3} = \textcolor{b l u e}{9}$

#### Explanation:

We will need to use the order of operations represented by the acronym PEMDAS.

P=parentheses and brackets
E=exponents or powers
MD=multiplication and division from left to right.
AS=addition and subtraction from left to right.

${\left(4 - 7\right)}^{2} \div {\left(7 - 6\right)}^{3}$

Simplify the parentheses first.

${\left(- 3\right)}^{2} \div {\left(1\right)}^{3}$

Now simplify the exponents.

$9 \div 1$

Simplify.

$9$