How do you evaluate #4( - 8) + 5( - 7)#?

1 Answer
EZ as pi
Feb 26, 2017

#= -67#

Explanation:

Notice that there are 2 terms. The number in front of each bracket must be multiplied by the number inside the bracket.

#4(-8) +(5(-7) #

#= (4xx-8) +(5xx-7)#

# = (-32)+(-35)#

This is addition of negative integers.

#= -67#

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