How do you evaluate #(4+ 8) \div ( 5- 1)#?

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Answer 1 · 2017-03-30T16:07:19

#3#

Solve based on PEMDAS. Work inside the parentheses first:

#4+8=12#

#5-1=4#

So now we have:

#12 -: 4#

We can simply solve for that:

#12 -: 4 =3#