Question

How do you evaluate `4+\tan ^{2}x-\frac{4}{\cot x}+\sin x\csc x`?

Answer 1

`(tanx)^2-4tanx+5`

Explanation:

`4+(tanx)^2-4/cotx+sinx*cscx`

=`4+(tanx)^2-4tanx+1`

=`(tanx)^2-4tanx+5`