How do you evaluate #(- 42) \div ( - 6) =#?

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Feb 11, 2017

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#7#

Explanation:

#(-42)-:(-6)#

#:.=(-42/1)-:(-6/1)#

#:.=-cancel42^7/1 xx-1/cancel6^1#

#:.=-7/1 xx -1/1#

#- xx - =+#

#:.=7#

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