How do you evaluate #(4r)/s# if #r=9# and #s=2#?

1 Answer
Dec 22, 2016

#(4r)/s=18#

Explanation:

When we have to evaluate a function having certain number of variables, where value of each valuable has already been give, we just substitute those values in the function and calculate the value of function.

Here we have to evaluate #(4r)/s#, where #r=9# and #s=2#

Hence #(4r)/s=(4xx9)/2=(cancel4^2xx9)/(cancel2^1)=18#