How do you evaluate #(- 5- 5i ) - ( 3i ) + ( 5i )#?

1 Answer

#-5-3i#

Explanation:

Remember that #i=sqrt(-1)# and so we can treat it just like another other square root of a prime number. In fact, let's first do the problem substituting in the square root:

#(-5-5i)-(3i)+(5i)#

#(-5-5sqrt(-1))-(3sqrt(-1))+(5sqrt(-1))#

#-5-5sqrt(-1)-3sqrt(-1)+5sqrt(-1)#

#-5-3sqrt(-1)#

And now let's substitute #i# back in:

#-5-3i#