Nov 9, 2015

$\frac{20}{\sqrt{3}} - \frac{3}{\sqrt{2}}$

#### Explanation:

You have that $\sqrt{\frac{a}{b}} = \frac{\sqrt{a}}{\sqrt{b}}$. So,

$\sqrt{\frac{16}{3}} = \frac{\sqrt{16}}{\sqrt{3}} = \frac{4}{\sqrt{3}}$.

Also,

$\sqrt{\frac{9}{2}} = \frac{\sqrt{9}}{\sqrt{2}} = \frac{3}{\sqrt{2}}$

Now that we have simplified the radicals, we can write the whole expression:

$5 \cdot \frac{4}{\sqrt{3}} - \frac{3}{\sqrt{2}} = \frac{20}{\sqrt{3}} - \frac{3}{\sqrt{2}}$