How do you evaluate #5x+8# for #x=3#?

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Answer 1 · 2018-05-21T14:38:47

See a solution process below:

Substitute #color(red)(3)# for #color(red)(x)# and calculate the result:

#5color(red)(x) + 8# becomes:

#(5 xx color(red)(3)) + 8 =>#

#15 + 8 =>#

#23#

Answer 2 · 2018-05-21T14:39:31

#23#

#"to evaluate substitute x = 3 into the expression"#

#rArr(5xxcolor(red)(3))+8=15+8=23#