How do you evaluate #6+(-7)+(-5)-(-2)#?

Question

3013 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-11T18:54:54

#-4#

#6+(-7)=-1#

#-1+(-5)=-6#

#-6-(-2)=-4#

Answer 2 · 2018-03-11T18:59:59

#-4#

Remove all the parenthesis taking into account that #+(-a) = -a# and #-(-a) = +a#

#6-7-5+2#

Add and/or subtract the values from the left to right

#6-7-5+2=-4#