How do you evaluate #0.684-:x# for #x=3#?

2 Answers
Mar 16, 2018

#0.684/x#

Explanation:

given that #x=3#

#rArr 0.684/3=0.228#

Mar 16, 2018

#0.684 div 3 = 0.228#

Explanation:

Divide as you would normally, You are not dividing by a decimal which is where you would need to adjust the question. Leave the decimal point in the same position.

#3|ul(0." "6" "8" "^2 4#
#" "0." "2" "2" "8#

#0 div 3 = 0#
#6 div3 = 2#
#8div3= 2 " remainder " 2# which carries to give #24#
#24 div 3 = 8#