Question

How do you evaluate `0.684-:x` for `x=3`?

Answer 1

`0.684/x`

Explanation:

given that `x=3`

`rArr 0.684/3=0.228`

Answer 2

`0.684 div 3 = 0.228`

Explanation:

Divide as you would normally, You are not dividing by a decimal which is where you would need to adjust the question. Leave the decimal point in the same position.

`3|ul(0." "6" "8" "^2 4`
`" "0." "2" "2" "8`

`0 div 3 = 0`
`6 div3 = 2`
`8div3= 2 " remainder " 2` which carries to give `24`
`24 div 3 = 8`