How do you evaluate #(6p + 13) ( 6p - 13)#?

1 Answer
Nov 29, 2017

See a solution process below:

Explanation:

Use this rule for quadratics:

#(color(red)(x) + color(blue)(y))(color(red)(x) - color(blue)(y)) = color(red)(x)^2 - color(blue)(y)^2#

Substituting gives:

#(color(red)(6p) + color(blue)(13))(color(red)(6p) - color(blue)(13)) = color(red)((6p))^2 - color(blue)(13)^2 = color(red)(36p^2) - color(blue)(169)#