How do you evaluate # (6x + 5)(9x +9)#?

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Answer 1 · 2017-08-04T04:47:48

See a solution process below:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(6x) + color(red)(5))(color(blue)(9x) + color(blue)(9))# becomes:

#(color(red)(6x) xx color(blue)(9x)) + (color(red)(6x) xx color(blue)(9)) + (color(red)(5) xx color(blue)(9x)) + (color(red)(5) xx color(blue)(9))#

#54x^2 + 54x + 45x + 45#

We can now combine like terms:

#54x^2 + (54 + 45)x + 45#

#54x^2 + 99x + 45#