# How do you evaluate 78 4/9 +11 7/9 ?

$\frac{812}{9}$ or 90$\frac{2}{9}$
$78 \left(\frac{4}{9}\right) + 11 \left(\frac{7}{9}\right)$ can be written as the sum of improper fractions $78 \cdot \frac{9}{4} + 11 \cdot \frac{9}{7} = \frac{706}{9} + \frac{106}{9} = \frac{812}{9}$ or 90$\frac{2}{9}$