How do you evaluate #(- 7k + 2s - 3q ) - ( - 2q - 3k ) + ( 4k + q - 2s )#?

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Answer 1 · 2018-01-30T06:35:09

0

Let’s start by making the equation to addition format (as it is easier to evaluate).

Note: Negative x Negative = Positive

So #(-7k+2s-3q)-(-2q-3k)+(4k+q-2s)#

Becomes #(-7k+2s-3q)+(2q+3k)+(4k+q-2s)#

Now we can group all the like terms together; move all the same variables together. Ill arrange it in brackets for you to get a better visual.

#(-7k+2s-3q)+(2q+3k)+(4k+q-2s)#

#(-7k+3k+4k)+(2s-2s)+(-3q+2q+q)#

#(-7k+7k)+(2s-2s)+(-3q+3q)#

#0 + 0 + 0 = 0#

Therefore answer is 0