How do you evaluate #8-(6r+2)#?

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Answer 1 · 2017-12-05T03:28:38

See a solution process below:

First, rewrite the expression by removing the parenthesis being careful to manage the signs of the individual terms correctly:

#8 - 6r - 2#

Next, group like terms:

#-6r + 8 - 2#

Now, combine like terms:

#-6r + (8 - 2)#

#-6r + 6#

Depending on the solution being looked for, we can rewrite this expression by factoring out a #color(red)(-6)#:

#(color(red)(-6) xx r) + (color(red)(-6) xx -1)#

#color(red)(-6)(r -1)#