Question

How do you evaluate `9- 4( x + 1) - 3= 9+ 2( 4- 2x ) - 16`?

Answer 1

No Solution or `cancel(0)`.

Explanation:

`9-4(x+1)-3 = 9+2(4-2x)-16`

First, combine like terms:
`6 - 4(x+1) = -7+2(4-2x)`

Now distribute/expand:
`6 - 4x - 4 = -7 + 8 - 4x`

`2 - 4x = 1 - 4x`

Subtract `color(blue)2` from both sides of the equation:
`2 - 4x quadcolor(blue)(-quad2) = 1 - 4x quadcolor(blue)(-quad2)`

`-4x = -1 - 4x`

Add `color(blue)(4x)` to both sides of the equation:
`-4x quadcolor(blue)(+quad4x) = -1 - 4x quadcolor(blue)(+quad4x)`

`0 = -1`

We don't have variables anymore! Now what we do is see if this equation is true. `0` does NOT equal to `-1`, so it is false.

When it is false, that means there is No Solution or `cancel(0)`.

Hope this helps!