How do you evaluate #c + (2a)^2# given a = 3 and c = −1?

1 Answer
Feb 16, 2017

Answer:

See the entire solution process below:

Explanation:

To evaluate this expression for the given values we must substitute #color(red)(3)# for #color(red)(a)# and substitute #color(blue)(-1)# for #color(blue)(c)# in the expression and then calculate the result:

#color(blue)(c) + (2color(red)(a))^2# becomes:

#color(blue)(-1) + (2 xx color(red)(3))^2 -> color(blue)(-1) + (6)^2 -> color(blue)(-1) + 36 -> 35#