# How do you evaluate c + (2a)^2 given a = 3 and c = −1?

To evaluate this expression for the given values we must substitute $\textcolor{red}{3}$ for $\textcolor{red}{a}$ and substitute $\textcolor{b l u e}{- 1}$ for $\textcolor{b l u e}{c}$ in the expression and then calculate the result:
$\textcolor{b l u e}{c} + {\left(2 \textcolor{red}{a}\right)}^{2}$ becomes:
$\textcolor{b l u e}{- 1} + {\left(2 \times \textcolor{red}{3}\right)}^{2} \to \textcolor{b l u e}{- 1} + {\left(6\right)}^{2} \to \textcolor{b l u e}{- 1} + 36 \to 35$