How do you evaluate #e^0.62#?

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Answer 1 · 2017-01-18T06:49:32

#e^0.62~~1.85893#

The value of #e^x# is given by

#1+x+x^2/(2!)+x^3/(3!)+x^4/(4!)+x^5/(5!)+...............................#

Hence #e^0.62# is given by

#1+0.62+0.62^2/(2!)+0.62^3/(3!)+0.62^4/(4!)+0.62^5/(5!)+...............................#

This is a well known convergent series and result is the irrational number and

#e^1=e=2.7182818284590452353602874713527........#

One can also find #e^0.62# using a scientific calculator, which
is roughly #~~1.85893#