Question

How do you evaluate `f(3s-3)` if `f(x) = 3(x+3)^2-5`?

Answer 1

Answer: `27s^2-5`

Explanation:

In function notation, the value or expression within the parentheses of `f(x)`, is what we plug into the function itself. Therefore, the question asks us to evaluate the function when `x=3s-3`:
`f(3s-3)=3((3s-3)+3)^2-5`
We can first cancel the `-3` with the `+3` inside the base of the square:
`=3(3s)^2-5`
Now, we can square the `(3s)^2` and simplify:
`=3(9s^2)-5`
`=27s^2-5`

Therefore, our final answer is `27s^2-5`.

Hope this helps!