How do you evaluate #\frac { 1} { 4} + - 1#?

2 Answers

Change both terms to fractions and add them algebraically

Explanation:

# -1 = - 1 xx 4/4 = - 4/4 # Changing the negative whole number to a fraction with the same denominator

# 1/4 +(- 4/4)#

#=1/4 -4/4#

# = - 3/4 #

The absolute value of the negative is larger, so the answer is negative.

Aug 13, 2017

#1/4 + -1=color(blue)(-3/4#

Refer to the explanation for the process.

Explanation:

Evaluate:

#1/4 + -1#

Any whole number #n# is understood to be #n/1#, so #-1=-1/1#. In order to add or subtract fractions, all denominators need to be the same. We can multiply a fraction by an #color(red)("equivalent fraction"# in order to change the denominator. An equivalent fraction equals #1#. Examples include #color(red)(3/3# and #color(red)(12/12#. You can see that #color(red)(3/3)=color(red)1# and #color(red)(12/12)=color(red)1# by dividing the numerator by the denominator. By doing this, we are not changing the value of the fraction.

Rewrite the original expression as:

#1/4-1/1# #larr# (A positive and a negative equal a negative.)

Multiply #-1/1# by an equivalent fraction that will convert the denominator to #4#.

#1/4-1/1xxcolor(red)(4/4#

Multiply the numerators and denominators across.

#1/4-(1xxcolor(red)(4))/(1xxcolor(red)(4))#

#1/4-4/4#

Place both numerators over the denominator and subtract.

#(1-4)/4=-3/4#