How do you evaluate #\frac { 2} { ( x + 1) ( x - 2) } - \frac { 3} { x ( x - 2) }#?

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Answer 1 · 2018-03-18T01:54:29

#-(x+3)/(x(x+1)(x-2))#

We need a common denominator:

#2/((x+1)(x-2))(1)-3/(x(x-2))(1)#

#2/((x+1)(x-2))(x/x)-3/(x(x-2))((x+1)/(x+1))#

#(2x)/(x(x+1)(x-2))-(3x+3)/(x(x+1)(x-2))#

#(2x-3x-3)/(x(x+1)(x-2))#

#(-x-3)/(x(x+1)(x-2))#

#-(x+3)/(x(x+1)(x-2))#