# How do you evaluate \int _ { 2} ^ { x} ( 3t ^ { 2} - 1) d t ?

Oct 26, 2017

${x}^{3} - x - 6$

#### Explanation:

Your antiderivative is going to be ${t}^{3} - t$

Evaluate that at t = 2:

${2}^{3} - 2 = 6$

Evaluate at t = x:

${x}^{3} - x$

...and subtract the lower limit value from the upper:

${x}^{3} - x - 6$
GOOD LUCK