How do you evaluate int dx/(x^2sqrt(x^2 - 9)) with x = 3sec(theta)?
Evaluate the integral using the indicated trigonometric substitution. (Use C for the constant of integration.)
int dx/(x^2sqrt(x^2 - 9)) , x = 3sec(theta )
Evaluate the integral using the indicated trigonometric substitution. (Use C for the constant of integration.)
1 Answer
Jul 5, 2018
Let
So