# How do you evaluate #ln sqrt(e)#?

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Apr 10, 2016

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**Recall that: #sqrtn=n^(1/2:#**

We can now express your equation as:

**Recall that: #log_na^m=mlog_na#**

We can further simplify the given equation:

**Recall that: #lne=log_ee=1#**

**We can now say that:**

Therefore,

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