How do you evaluate #log_2 4 - log_2 16#? Precalculus Properties of Logarithmic Functions Logarithm-- Inverse of an Exponential Function 1 Answer MeneerNask Jul 9, 2015 Since #4=2^2and 16=2^4# we can rewrite: Explanation: #=log_2 2^2-log_2 2^4# Exponent rule: #=2*log_2 2-4*log_2 2# Since #log_b b=1# for any #b->log_2 2=1# #=2*1-4*1=-2# Answer link Related questions What is a logarithm? What are common mistakes students make with logarithms? How can a logarithmic equation be solved by graphing? How can I calculate a logarithm without a calculator? How can logarithms be used to solve exponential equations? How do logarithmic functions work? What is the logarithm of a negative number? What is the logarithm of zero? How do I find the logarithm #log_(1/4) 1/64#? How do I find the logarithm #log_(2/3)(8/27)#? See all questions in Logarithm-- Inverse of an Exponential Function Impact of this question 2983 views around the world You can reuse this answer Creative Commons License