# How do you evaluate #log_2 8#?

##### 2 Answers

Aug 10, 2018

#### Explanation:

#"using the "color(blue)"law of logarithms"#

#•color(white)(x)log_b x=nhArrx=b^n#

#"let "log_2 8=nhArr8=2^nrArrn=3#

#rArrlog_2 8=3#

Aug 11, 2018

Using logarithm properties we have