How do you evaluate #log_3(1/27)#? Precalculus Properties of Logarithmic Functions Functions with Base b 1 Answer Özgür Özer Dec 19, 2015 #color(white)(xx)-3# Explanation: #color(white)(xx)log_3 (1/27)=log_3 (1/3^3)# #color(white)(xxxxxxxxx)=log_3 3^-3# #color(white)(xxxxxxxxx)=-3xxlog_3 3# (The logarithm of the power of a number rule) #color(white)(xxxxxxxxx)=-3xx1# #color(white)(xxxxxxxxx)=-3# Answer link Related questions What is the exponential form of #log_b 35=3#? What is the product rule of logarithms? What is the quotient rule of logarithms? What is the exponent rule of logarithms? What is #log_b 1#? What are some identity rules for logarithms? What is #log_b b^x#? What is the reciprocal of #log_b a#? What does a logarithmic function look like? How do I graph logarithmic functions on a TI-84? See all questions in Functions with Base b Impact of this question 16529 views around the world You can reuse this answer Creative Commons License