How do you evaluate log_(3) 2 times log_(2) 27?

I found $3$
${\log}_{3} \left(2\right) \times \frac{{\log}_{3} \left(27\right)}{{\log}_{3} \left(2\right)} =$
$= \cancel{{\log}_{3} \left(2\right)} \times \frac{{\log}_{3} \left(27\right)}{\cancel{\left({\log}_{3} \left(2\right)\right)}} = {\log}_{3} \left(27\right) = 3$