# How do you evaluate #log_[6](144) - log_[6](4)#?

##### 1 Answer

Apr 4, 2016

#### Explanation:

Use the identity

#log_x(a) - log_x(b) = log_x(a/b)#

Thus,

#log_6(144) - log_6(4) = log_6(144/4)#

# = log_6(36)#

# = log_6(6^2)#

# = 2#