How do you evaluate  Log _ 9(1/3)?

$\textcolor{w h i t e}{\times} - \frac{1}{2}$
$\textcolor{w h i t e}{\times} {\log}_{9} \left(\frac{1}{3}\right) = {\log}_{{3}^{2}} {3}^{-} 1$
$\textcolor{w h i t e}{\times \times \times \times} = \frac{1}{2} \times \left(- 1\right) {\log}_{3} 3$
$\textcolor{w h i t e}{\times \times \times \times} = - \frac{1}{2}$