How do you evaluate #\root[ 5] { 32x }#?

1 Answer
Jun 28, 2017

See a solution process below:

Explanation:

We can rewrite this expression as:

#root(5)(32 * x)#

We can next use this rule for radicals to rewrite this expression:

# root(n)(color(red)(a) * color(blue)(b)) = root(n)(color(red)(a)) * root(n)(color(blue)(b))#

# root(5)(color(red)(32) * color(blue)(x)) = root(5)(color(red)(32)) * root(5)(color(blue)(x)) = root(5)(color(red)(2 * 2 * 2 * 2 * 2)) * root(5)(color(blue)(x)) =#

#2root(5)(x)#