# How do you evaluate sin^-1(sin((13pi)/6))?

Dec 13, 2016

The answer is $\frac{13 \pi}{6}$.

#### Explanation:

Suppose ${\sin}^{-} 1$ or $\arcsin$ or inverse $\sin$ of a value $x$ is $y$,
i.e. ${\sin}^{-} 1 x = y$.

This means that $\sin y = x$.

In this case, we have to evaluate inverse $\sin$ of $\sin \left(\frac{13 \pi}{6}\right)$, which will be $\frac{13 \pi}{6}$.